Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 8 - Section 8.1 - Review of Equations of Lines and Writing Parallel and Perpendicular Lines - Exercise Set - Page 573: 28

Answer

y=-$\frac{3}{2}$x+2

Work Step by Step

2x-3y=1 -3y=-2x+1 y=$\frac{-2x+1}{-3}$ y=$\frac{2x}{3}$-$\frac{1}{3}$ y=$\frac{2}{3}$x-$\frac{1}{3}$ slope is $\frac{2}{3}$ line perpendicular,slope is -$\frac{3}{2}$,through (-4;8) y=mx+b 8=-$\frac{3}{2}$(-4)+b 8=6+b b=2 y=mx+b y=-$\frac{3}{2}$x+2
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.