#### Answer

$\dfrac{\dfrac{-3+y}{4}}{\dfrac{8+y}{28}}=\dfrac{7(y-3)}{y+8}$

#### Work Step by Step

$\dfrac{\dfrac{-3+y}{4}}{\dfrac{8+y}{28}}$
Evaluate the division and simplify:
$\dfrac{\dfrac{-3+y}{4}}{\dfrac{8+y}{28}}=\dfrac{-3+y}{4}\div\dfrac{8+y}{28}=\dfrac{(-3+y)(28)}{(8+y)(4)}=\dfrac{7(y-3)}{y+8}$