## Algebra: A Combined Approach (4th Edition)

$\dfrac{\dfrac{4y-8}{16}}{\dfrac{6y-12}{4}}=\dfrac{1}{6}$
$\dfrac{\dfrac{4y-8}{16}}{\dfrac{6y-12}{4}}$ Evaluate the division: $\dfrac{\dfrac{4y-8}{16}}{\dfrac{6y-12}{4}}=\dfrac{4y-8}{16}\div\dfrac{6y-12}{4}=\dfrac{(4)(4y-8)}{(16)(6y-12)}=...$ Take out common factor $4$ from the second parentheses in the numerator and common factor $6$ from the second parentheses in the denominator. After that, simplify: $...=\dfrac{(4)(4)(y-2)}{(16)(6)(y-2)}=\dfrac{16}{(16)(6)}=\dfrac{1}{6}$