Answer
$\dfrac{\dfrac{3}{5y}+8}{\dfrac{3}{5y}-8}=\dfrac{40y+3}{3-40y}$
Work Step by Step
$\dfrac{\dfrac{3}{5y}+8}{\dfrac{3}{5y}-8}$
Evaluate the sum indicated in the numerator and the substraction indicated in the denominator:
$\dfrac{\dfrac{3}{5y}+8}{\dfrac{3}{5y}-8}=\dfrac{\dfrac{3+40y}{5y}}{\dfrac{3-40y}{5y}}=...$
Evaluate the division and simplify:
$...=\dfrac{3+40y}{5y}\div\dfrac{3-40y}{5y}=\dfrac{5y(3+40y)}{5y(3-40y)}=\dfrac{40y+3}{3-40y}$
