Answer
$\dfrac{\dfrac{6x-3}{5x^{2}}}{\dfrac{2x-1}{10x}}=\dfrac{6}{x}$
Work Step by Step
$\dfrac{\dfrac{6x-3}{5x^{2}}}{\dfrac{2x-1}{10x}}$
Evaluate the division:
$\dfrac{\dfrac{6x-3}{5x^{2}}}{\dfrac{2x-1}{10x}}=\dfrac{6x-3}{5x^{2}}\div\dfrac{2x-1}{10x}=\dfrac{(6x-3)(10x)}{(5x^{2})(2x-1)}=...$
Take out common factor $3$ from the first parentheses of the numerator and simplify:
$...=\dfrac{3(2x-1)(10x)}{(5x^{2})(2x-1)}=\dfrac{3(10x)}{5x^{2}}=\dfrac{3(2)}{x}=\dfrac{6}{x}$