## Algebra: A Combined Approach (4th Edition)

$\dfrac{\dfrac{6x-3}{5x^{2}}}{\dfrac{2x-1}{10x}}=\dfrac{6}{x}$
$\dfrac{\dfrac{6x-3}{5x^{2}}}{\dfrac{2x-1}{10x}}$ Evaluate the division: $\dfrac{\dfrac{6x-3}{5x^{2}}}{\dfrac{2x-1}{10x}}=\dfrac{6x-3}{5x^{2}}\div\dfrac{2x-1}{10x}=\dfrac{(6x-3)(10x)}{(5x^{2})(2x-1)}=...$ Take out common factor $3$ from the first parentheses of the numerator and simplify: $...=\dfrac{3(2x-1)(10x)}{(5x^{2})(2x-1)}=\dfrac{3(10x)}{5x^{2}}=\dfrac{3(2)}{x}=\dfrac{6}{x}$