## Algebra: A Combined Approach (4th Edition)

Answer: $\frac{2}{3}$
$\frac{\frac{-4x}{9}}{\frac{-2x}{3}}$ = $\frac{-4x}{9}$ $\div$ $\frac{-2x}{3}$ $\frac{-4x}{9}$ $\div$ $\frac{-2x}{3}$ = $\frac{-4x}{9}$ $\times$ $\frac{-3}{2x}$ = $\frac{2x(-2) \times 3(-1)}{3(3) \times 2x}$ = $\frac{2}{3}$ .....(Since: $\frac{2x}{2x}$=1, (-1)(-2)=2, $\frac{3}{3}$=1).