Answer
$\dfrac{\dfrac{x}{2}+2}{\dfrac{x}{2}-2}=\dfrac{x+4}{x-4}$
Work Step by Step
$\dfrac{\dfrac{x}{2}+2}{\dfrac{x}{2}-2}$
Evaluate the sum indicated in the numerator and the substraction indicated in the denominator:
$\dfrac{\dfrac{x}{2}+2}{\dfrac{x}{2}-2}=\dfrac{\dfrac{x+4}{2}}{\dfrac{x-4}{2}}=...$
Evaluate the division and simplify if possible:
$...=\dfrac{x+4}{2}\div\dfrac{x-4}{2}=\dfrac{(x+4)(2)}{(x-4)(2)}=\dfrac{x+4}{x-4}$
