Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.7 - Simplifying Complex Fractions - Exercise Set - Page 548: 5

Answer

$\dfrac{\dfrac{1+x}{6}}{\dfrac{1+x}{3}}=\dfrac{1}{2}$

Work Step by Step

$\dfrac{\dfrac{1+x}{6}}{\dfrac{1+x}{3}}$ Evaluate the division and simplify: $\dfrac{\dfrac{1+x}{6}}{\dfrac{1+x}{3}}=\dfrac{1+x}{6}\div\dfrac{1+x}{3}=\dfrac{(1+x)(3)}{(1+x)(6)}=\dfrac{1}{2}$
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