## Algebra: A Combined Approach (4th Edition)

$\dfrac{x^{2}-25}{x^{2}-3x-10}\cdot\dfrac{x+2}{x}=\dfrac{x+5}{x}$
$\dfrac{x^{2}-25}{x^{2}-3x-10}\cdot\dfrac{x+2}{x}$ Factor the numerator and the denominator of the first fraction: $\dfrac{x^{2}-25}{x^{2}-3x-10}\cdot\dfrac{x+2}{x}=\dfrac{(x-5)(x+5)}{(x+2)(x-5)}\cdot\dfrac{x+2}{x}=...$ Multiply both rational expressions and simplify by removing repeated factors in the numerator and the denominator: $...=\dfrac{(x-5)(x+5)(x+2)}{x(x+2)(x-5)}=\dfrac{x+5}{x}$