## Algebra: A Combined Approach (4th Edition)

$\dfrac{(x+3)^{2}}{5}\div\dfrac{5x+15}{25}=x+3$
$\dfrac{(x+3)^{2}}{5}\div\dfrac{5x+15}{25}$ Take out common factor $5$ from the numerator of the second fraction: $\dfrac{(x+3)^{2}}{5}\div\dfrac{5x+15}{25}=\dfrac{(x+3)^{2}}{5}\div\dfrac{5(x+3)}{25}=...$ Evaluate the division of the two rational expressions and simplify by removing repeated factors in the numerator and the denominator: $...=\dfrac{25(x+3)^{2}}{25(x+3)}=x+3$