#### Answer

$\dfrac{(x+3)^{2}}{5}\div\dfrac{5x+15}{25}=x+3$

#### Work Step by Step

$\dfrac{(x+3)^{2}}{5}\div\dfrac{5x+15}{25}$
Take out common factor $5$ from the numerator of the second fraction:
$\dfrac{(x+3)^{2}}{5}\div\dfrac{5x+15}{25}=\dfrac{(x+3)^{2}}{5}\div\dfrac{5(x+3)}{25}=...$
Evaluate the division of the two rational expressions and simplify by removing repeated factors in the numerator and the denominator:
$...=\dfrac{25(x+3)^{2}}{25(x+3)}=x+3$