#### Answer

$\dfrac{x}{2x-14}\cdot\dfrac{x^{2}-7x}{5}=\dfrac{x^{2}}{10}$

#### Work Step by Step

$\dfrac{x}{2x-14}\cdot\dfrac{x^{2}-7x}{5}$
Factor the denominator of the first fraction by taking out common factor $2$:
$\dfrac{x}{2x-14}\cdot\dfrac{x^{2}-7x}{5}=\dfrac{x}{2(x-7)}\cdot\dfrac{x^{2}-7x}{5}=...$
Factor the numerator of the second fraction by taking out common factor $x$:
$...=\dfrac{x}{2(x-7)}\cdot\dfrac{x(x-7)}{5}=...$
Multiply both rational expressions and simplify by removing repeated factors in the numerator and the denominator:
$...=\dfrac{x^{2}(x-7)}{10(x-7)}=\dfrac{x^{2}}{10}$