Answer
$\frac{9}{2}$
Work Step by Step
$\frac{9y^{4}}{6y}$$\div$$\frac{y^{2}}{3}$=
$\frac{9y^{4}}{6y}$$\times$$\frac{3}{y^{2}}$=
$\frac{3y^{3}}{2}$$\times$$\frac{3}{y^{2}}$=
$\frac{9}{2}$
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