Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Review - Page 560: 73

Answer

1

Work Step by Step

Let $x$ be the number Since the quotient of twice the number and 3, minus one-sixth, is the quotient of the number and 2, we have, $\frac{2x}{3}$ - $\frac{1}{6}$ = $\frac{x}{2}$ $\frac{4x}{6}$ - $\frac{1}{6}$ = $\frac{3x}{6}$ (LCD = 6) $4x - 1 = 3x$ $x = 1$ Therefore, the number is 1.
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