## Algebra: A Combined Approach (4th Edition)

$a=\dfrac{1}{2}$
$\dfrac{4}{a-1}+2=\dfrac{3}{a-1}$ Multiply the whole equation by $a-1$: $(a-1)\Big(\dfrac{4}{a-1}+2=\dfrac{3}{a-1}\Big)$ $4+2(a-1)=3$ Solve for $a$: $4+2a-2=3$ $2a+2=3$ $2a=3-2$ $2a=1$ $a=\dfrac{1}{2}$ Since the initial equation is not undefined for this value of $a$, we have found the answer. The solution to this equation is $a=\dfrac{1}{2}$