Answer
$\dfrac{x}{x^{2}-36}+\dfrac{6}{x^{2}-36}=\dfrac{1}{x-6}$
Work Step by Step
$\dfrac{x}{x^{2}-36}+\dfrac{6}{x^{2}-36}$
Evaluate the sum:
$\dfrac{x}{x^{2}-36}+\dfrac{6}{x^{2}-36}=\dfrac{x+6}{x^{2}-36}=...$
Factor the denominator and simplify:
$...=\dfrac{x+6}{(x-6)(x+6)}=\dfrac{1}{x-6}$