## Algebra: A Combined Approach (4th Edition)

$\dfrac{x}{x+3}+4=\dfrac{x}{x+3}$ Multiply the whole equation by $x+3$: $(x+3)\Big(\dfrac{x}{x+3}+4=\dfrac{x}{x+3}\Big)$ $x+4(x+3)=x$ Solve for $x$: $x+4x+12=x$ $5x-x=-12$ $4x=-12$ $x=-\dfrac{12}{4}$ $x=-3$ The original equation is undefined for this value of $x$, so this equation has no solution.