# Chapter 6 - Review: 61

The solution is $\frac{1}{3}$.

#### Work Step by Step

(3x-1)(9$x^{2}$+3x+1)=0 (3x-1) =0 or (9$x^{2}$+3x+1)=0 3x-1+1=0+1 or (9$x^{2}$+3x+1)=0 3x=1 or no solution x=$\frac{1}{3}$ The solution is $\frac{1}{3}$. Check Let x= $\frac{1}{3}$ (3x-1)(9$x^{2}$+3x+1)=0 (3*$\frac{1}{3}$-1)(9*$(1/3)^{2}$+3*1/3+1)=0 (1-1)(9*$(1/3)^{2}$+3*1/3+1)=0 0*(9*$(1/3)^{2}$+3*1/3+1)=0 0=0

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