Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 6 - Review: 44

Answer

$ (2x - 1)(2x + 1)(4x^2 + 1)$

Work Step by Step

$16x^4-1 = (4x^2)^2 - (1)^2 = (4x^2- 1)( 4x^2+ 1) = ((2x)^2 - (1)^2)(4x^2 + 1) = (2x - 1)(2x + 1)(4x^2 + 1)$
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