# Chapter 6 - Review - Page 474: 56

The solutions are $\frac{-1}{5}$ and -3.

#### Work Step by Step

4(5x+1)(x+3)=0 5x+1=0 or x+3=0 5x+1-1=0 -1 or x+3-3=0-3 5x= -1 or x=-3 x=$\frac{-1}{5}$ The solutions are $\frac{-1}{5}$ and -3. Check Let x=-3 4(5x+1)(x+3)=0 4[5(-3)+1](-3+3)=0 4[5(-3)+1]0=0 0=0 Let x=$\frac{-1}{5}$ 4(5x+1)(x+3)=0 4[5*$\frac{-1}{5}$+1](-1+3)=0 4(-1+1)2=0 4*0*2=0 0=0

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