## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 6 - Review - Page 474: 47

#### Answer

(2-3y)(4+6y+9$y^{2}$)

#### Work Step by Step

8-27$y^{3}$=$2^{3}$-$(3y)^{3}$=(2-3y)[$2^{2}$+2(3y)+$(3y)^{2}$= (2-3y)(4+6y+9$y^{2}$)

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