## Algebra: A Combined Approach (4th Edition)

Answer: $2m-\frac{27m^{2}}{7}$ (or $\frac{7m-27m^{2}}{7}$ )
Given: $\frac{14m^{2}-27m^{3}}{7m}$ = $\frac{7(2)(m)(m)-27(m)(m)(m)}{7m}$ ......(Since $m^{2}=(m)(m)$ and $m^{3}=(m)(m)(m)$ This is equal to : $\frac{7m(2m)}{7m}$ - $\frac{27(m)(m)(m)}{7m}$ = $2m- \frac{27(m)(m)}{7}$ .....(Since $\frac{7m}{7m}=1$ and $\frac{m}{m}=1$) = $2m-\frac{27m^{2}}{7}$ or = $\frac{7m-27m^{2}}{7}$