Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.7 - Dividing Polynomials - Exercise Set - Page 396: 8


Answer: $2m-\frac{27m^{2}}{7}$ (or $\frac{7m-27m^{2}}{7}$ )

Work Step by Step

Given: $\frac{14m^{2}-27m^{3}}{7m}$ = $\frac{7(2)(m)(m)-27(m)(m)(m)}{7m}$ ......(Since $m^{2}=(m)(m)$ and $m^{3}=(m)(m)(m)$ This is equal to : $\frac{7m(2m)}{7m}$ - $\frac{27(m)(m)(m)}{7m}$ = $2m- \frac{27(m)(m)}{7}$ .....(Since $\frac{7m}{7m}=1$ and $\frac{m}{m}=1$) = $2m-\frac{27m^{2}}{7}$ or = $\frac{7m-27m^{2}}{7}$
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