Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.7 - Dividing Polynomials - Exercise Set - Page 396: 10



Work Step by Step

$\frac{6a^2-4a+12}{-2a^2}$ $=6a^2(\frac{1}{-2a^2})-4a(\frac{1}{-2a^2})+12(\frac{1}{-2a^2})$ $=-3+\frac{2}{a}-\frac{6}{a^2}$
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