Answer
$-3+\frac{2}{a}-\frac{6}{a^2}$
Work Step by Step
$\frac{6a^2-4a+12}{-2a^2}$
$=6a^2(\frac{1}{-2a^2})-4a(\frac{1}{-2a^2})+12(\frac{1}{-2a^2})$
$=-3+\frac{2}{a}-\frac{6}{a^2}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 5 - Section 5.7 - Dividing Polynomials - Exercise Set - Page 396: 10
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