Answer
$-1+\frac{3}{2x}-\frac{7}{4x^4}$
Work Step by Step
$\frac{4x^4-6x^3+7}{-4x^4}$
$=4x^4(\frac{1}{-4x^4})-6x^3(\frac{1}{-4x^4})+7(\frac{1}{-4x^4})$
$=-1+\frac{3}{2x}-\frac{7}{4x^4}$
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