Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.7 - Dividing Polynomials - Exercise Set - Page 396: 4


Answer: $4x^{3}-2x^{2}+3x+1$

Work Step by Step

Given: $\frac{8x^{3}-4x^{2}+6x+2}{2}$ = $\frac{(2)4x^{3}-(2)2x^{2}+(2)3x+(2)1}{2}$ This is equal to : $\frac{(2)4x^{3}}{2}$ - $\frac{(2)2x^{2}}{2}$ + $\frac{(2)3x}{2}$ + $\frac{(2)1}{2}$ =$4x^{3}-2x^{2}+3x+1$ .....(Since $\frac{2}{2}=1$ )
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