## Algebra: A Combined Approach (4th Edition)

Answer: $4x^{3}-2x^{2}+3x+1$
Given: $\frac{8x^{3}-4x^{2}+6x+2}{2}$ = $\frac{(2)4x^{3}-(2)2x^{2}+(2)3x+(2)1}{2}$ This is equal to : $\frac{(2)4x^{3}}{2}$ - $\frac{(2)2x^{2}}{2}$ + $\frac{(2)3x}{2}$ + $\frac{(2)1}{2}$ =$4x^{3}-2x^{2}+3x+1$ .....(Since $\frac{2}{2}=1$ )