Answer
$\frac{2y^{8}}{3}$
Work Step by Step
$\frac{2x^{4}y^{12}}{3x^{4}y^{4}}=\frac{2x^{4-4}y^{12-4}}{3}=\frac{2x^{0}y^{8}}{3}=\frac{2(1)y^{8}}{3}= \frac{2y^{8}}{3}$
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