Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.6 - Special Products - Exercise Set: 85

Answer

$\frac{-2a^{10}}{b^{5}}$

Work Step by Step

$\frac{8a^{17}b^{5}}{-4a^{7}b^{10}}=\frac{8a^{17-7}b^{5-10}}{-4}=\frac{8a^{10}b^{-5}}{-4}=\frac{2a^{10}b^{-5}}{-1}=\frac{-2a^{10}}{b^{5}}$
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