Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.6 - Special Products - Exercise Set: 83

Answer

$ \frac{5}{7}b^5$

Work Step by Step

$\frac{50b^{10}}{70b^5} = \frac{50b^{10-5}}{70} = \frac{50b^5}{70} = \frac{5}{7}b^5$
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