Answer
Answer:
$4x^{2}+4x+1$
Work Step by Step
$(2x+1)^{2}$
Take any number, say $'a'$ . For squaring that number: $a^{2}$, we multiply that number by itself: $a^{2}$ = $a\times a$
Thus, here the number is $(2x+1)$.
Thus, $(2x+1)^{2}$ = $(2x+1)\times (2x+1)$
=$2x(2x+1)+1(2x+1)$
=$4x^{2}+2x+2x+1$
=$4x^{2}+4x+1$