Answer
$6y^{2}+11y-35$
Work Step by Step
Using the FOIL method, $(3y-5)(2y+7)=(3y)(2y)+(3y)(7)+(-5)(2y)+(-5)(7)=6y^{2}+21y+(-10y)+(-35)=6y^{2}+21y-10y-35=6y^{2}+11y-35$.
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