Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.6 - Special Products - Exercise Set: 11

Answer

$6y^{3}+4y^{2}+42y+28$

Work Step by Step

Using the FOIL method, $(y^{2}+7)(6y+4)=(y^{2})(6y)+(y^{2})(4)+(7)(6y)+(7)(4)=6y^{2+1}+4y^{2}+42y+28=6y^{3}+4y^{2}+42y+28$.
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