Answer
$y^{2}-\dfrac{3}{2}y+\dfrac{9}{16}$
Work Step by Step
$\Big(y-\dfrac{3}{4}\Big)^{2}$
Apply the formula for squaring a binomial, which is $(a-b)^{2}=a^{2}-2ab+b^{2}$
Here, $a=y$ and $b=\dfrac{3}{4}$
$\Big(y-\dfrac{3}{4}\Big)^{2}=y^{2}-2(y)\Big(\dfrac{3}{4}\Big)+\Big(\dfrac{3}{4}\Big)^{2}=y^{2}-\dfrac{3}{2}y+\dfrac{9}{16}$
