Answer
$y^{2}-8y-48$
Work Step by Step
Using the FOIL method, $(y-12)(y+4)=(y)(y)+(y)(4)+(-12)(y)+(-12)(4)=y^{2}+4y+(-12y)+(-48)=y^{2}+4y-12y-48=y^{2}-8y-48$.
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