Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.1 - Exponents - Exercise Set: 28

Answer

$a^{15}b^{18}$

Work Step by Step

Based on the product rule for exponents, we know that $a^{m}\times a^{n}=a^{m+n}$ (where $m$ and $n$ are positive integers and $a$ is a real number). Therefore, $(a^{2}b)\times(a^{13}b^{17})=a^{2+13}\times b^{1+17}=a^{15}\times b^{18}=a^{15}b^{18}$.
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