Answer
$-\frac{10}{81}$
Work Step by Step
We are asked to evaluate $\frac{10}{3y^{3}}$ when $y=-3$. We can plug in the given value directly and evaluate.
$\frac{10}{3y^{3}}=\frac{10}{3\times(-3)^{3}}=\frac{10}{3\times-27}=\frac{10}{-81}=-\frac{10}{81}$
