Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.1 - Exponents - Exercise Set - Page 343: 18



Work Step by Step

We are asked to evaluate $-4x^{2}y^{3}$ when $x=2$ and $y=-1$. We can plug in the given value directly and evaluate. $-4x^{2}y^{3}=-4\times2^{2}\times(-1)^{3}=-4\times(2\times2)\times(-1\times-1\times-1)=-4\times4\times-1=16$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.