Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.1 - Exponents - Exercise Set - Page 343: 18

Answer

16

Work Step by Step

We are asked to evaluate $-4x^{2}y^{3}$ when $x=2$ and $y=-1$. We can plug in the given value directly and evaluate. $-4x^{2}y^{3}=-4\times2^{2}\times(-1)^{3}=-4\times(2\times2)\times(-1\times-1\times-1)=-4\times4\times-1=16$
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