Answer
$4z^{5}$
Work Step by Step
Based on the product rule for exponents, we know that $a^{m}\times a^{n}=a^{m+n}$ (where $m$ and $n$ are positive integers and $a$ is a real number).
Therefore, $(-2z^{3})\times(-2z^{2})=(-2)^{1+1}\times z^{3+2}=(-2)^{2}\times z^{5}=4z^{5}$.