Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Review: 44

Answer

$\frac{b^3}{5a^6c^7}$

Work Step by Step

$\frac{8a^0b^4c^5}{40a^6bc^{12}}$ $=\frac{1}{5}a^{0-6}b^{4-1}c^{5-12}$ $=\frac{1}{5}a^{-6}b^{3}c^{-7}$ $=\frac{b^3}{5a^6c^7}$
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