Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Review: 41

Answer

$c^{4}$

Work Step by Step

Step 1: $(\frac{bc^{-2}}{bc^{-3}})^{4}$ Step 2: $\frac{(bc^{-2})^{4}}{(bc^{-3})^{4}}$ Step 3: $\frac{b^{4}(c^{-2})^{4}}{b^{4}(c^{-3})^{4}}$ Step 4: $\frac{b^{4}c^{-8}}{b^{4}c^{-12}}$ Step 5: Cancelling $b^{4}$ as it is common to both the numerator and the denominator, we get $\frac{c^{-8}}{c^{-12}}.$ Step 6: $\frac{c^{-8}}{c^{-12}}=c^{-8+12}=c^{4}$
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