Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Review - Page 404: 43

Answer

$\frac{a^2}{5b^7c^3}$

Work Step by Step

$\frac{10a^3b^4c^0}{50ab^{11}c^3}$ $=\frac{1}{5}a^{3-1}b^{4-11}c^{0-3}$ $=\frac{1}{5}a^2b^{-7}c^{-3}$ $=\frac{a^2}{5b^7c^3}$
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