#### Answer

$(-\frac{2}{3}, \frac{2}{5})$

#### Work Step by Step

$\frac{3}{5}x-y=-\frac{4}{5}$
$3x+\frac{y}{2}=-\frac{9}{5}$
Multiply first equation by 5 and second equation by 10.
$3x-5y=-4$
$30x+5y=-18$
Add both equations.
$33x=-22$
$x=-\frac{2}{3}$
Solve for $y$.
$\frac{3}{5}x-y=-\frac{4}{5}$
$\frac{3}{5}(-\frac{2}{3})-y=-\frac{4}{5}$
$-\frac{2}{5}-y=-\frac{4}{5}$
$y=\frac{2}{5}$
$x=-\frac{2}{3}$
$y=\frac{2}{5}$
$(-\frac{2}{3}, \frac{2}{5})$