Algebra: A Combined Approach (4th Edition)

$(3,12)$
$2x-\frac{3y}{4}=-3$ $x+\frac{y}{9}=\frac{13}{3}$ Multiply the first equation by 4 and the second equation by 9. $8x-3y=-12$ $9x+y=39$ Multiply the second equation by 3. $8x-3y=-12$ $27x+3y=117$ Add both equations. $35x=105$ $x=3$ Solve for $y$. $2x-\frac{3y}{4}=-3$ $2(3)-\frac{3y}{4}=-3$ $6-\frac{3y}{4}=-3$ $\frac{3y}{4}=9$ $3y=36$ $y=12$ $x=3; y=12$ $(3,12)$