#### Answer

$(-\frac{1}{2},-2)$

#### Work Step by Step

$-4(x+2)=3y$
$2x-2y=3$
Expand and arrange the first equation.
$-4x-8=3y$
$-4x-3y=8$
$-4x-3y=8$
$2x-2y=3$
Multiply the second equation by 2.
$-4x-3y=8$
$4x-4y=6$
Add both equations.
$-7y=14$
$y=-2$
Solve for $x$.
$2x-2y=3$
$2x-2(-2)=3$
$2x+4=3$
$2x=-1$
$x=-\frac{1}{2}$
$x=-\frac{1}{2}; y=-2$
$(-\frac{1}{2},-2)$