Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.3 - Solving Systems of Linear Equations by Addition - Exercise Set - Page 308: 31



Work Step by Step

$x-\frac{y}{3}=-1$ $-\frac{x}{2}+\frac{y}{8}=\frac{1}{4}$ Multiply the first equation by 3 and second equation by 8. $3x-y=-3$ $-4x+y=2$ Add both equations. $-x=-1$ $x=1$ Solve for $y$. $x-\frac{y}{3}=-1$ $(1)-\frac{y}{3}=-1$ $y=6$ $x=1; y=6$ $(1,6)$
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