Answer
$(1,6)$
Work Step by Step
$x-\frac{y}{3}=-1$
$-\frac{x}{2}+\frac{y}{8}=\frac{1}{4}$
Multiply the first equation by 3 and second equation by 8.
$3x-y=-3$
$-4x+y=2$
Add both equations.
$-x=-1$
$x=1$
Solve for $y$.
$x-\frac{y}{3}=-1$
$(1)-\frac{y}{3}=-1$
$y=6$
$x=1; y=6$
$(1,6)$
