Answer
When $x=2$ , $y=4$
When $x=-1$ , $y=1$
Work Step by Step
Given:
$y=x^{2}$
$y=x+2$
Comparing both equations,
$y=x^{2}=x+2$
Thus,
$x^{2}=x+2$
$\Rightarrow$ $x^{2}-x-2=0$
$\Rightarrow$ $x^{2}-2x+x-2=0$
$\Rightarrow$ $x(x-2)+1(x-2)=0$
$\Rightarrow$ $(x-2)(x+1)=0$
$\Rightarrow$ $x=2$ or $x=-1$
When $x=2$, $y=x^{2}$ $\Rightarrow$ $y=4$
When $x=-1$, $y=x^{2}$ $\Rightarrow$ $y=1$
