Answer
$(f\circ g)(x)=3x+11$
$(g\circ f)(x)=3x+31$
Work Step by Step
$f(x)=x+10;$ $g(x)=3x+1$
$(f\circ g)(x)$
To find $(f\circ g)(x)$, substitute $x$ by $g(x)$ in $f(x)$ and simplify:
$(f\circ g)(x)=f(g(x))=(3x+1)+10=3x+11$
$(g\circ f)(x)$
To find $(g\circ f)(x)$, substitute $x$ by $f(x)$ in $g(x)$ and simplify:
$(g\circ f)(x)=g(f(x))=3(x+10)+1=3x+30+1=3x+31$
