Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.1 - The Algebra of Functions - Exercise Set: 18

Answer

$(f\circ g)(x)=3x+11$ $(g\circ f)(x)=3x+31$

Work Step by Step

$f(x)=x+10;$ $g(x)=3x+1$ $(f\circ g)(x)$ To find $(f\circ g)(x)$, substitute $x$ by $g(x)$ in $f(x)$ and simplify: $(f\circ g)(x)=f(g(x))=(3x+1)+10=3x+11$ $(g\circ f)(x)$ To find $(g\circ f)(x)$, substitute $x$ by $f(x)$ in $g(x)$ and simplify: $(g\circ f)(x)=g(f(x))=3(x+10)+1=3x+30+1=3x+31$
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