## Algebra: A Combined Approach (4th Edition)

$(h\circ f)(-2)=3\sqrt{2}\approx42426$
$f(x)=x^{2}-6x+2;$ $h(x)=\sqrt{x}$ $(h\circ f)(-2)$ First, find $f(-2)$ by substituting $x$ by $-2$ in $f(x)$: $f(-2)=(-2)^{2}-6(-2)+2=4+12+2=18$ Find $(h\circ f)(-2)$ by substituting $x$ by $18$ in $h(x)$: $(h\circ f)(-2)=h(18)=\sqrt{18}=\sqrt{2\cdot9}=3\sqrt{2}\approx4.2426$