Answer
$(h\circ f)(-2)=3\sqrt{2}\approx42426$
Work Step by Step
$f(x)=x^{2}-6x+2;$ $h(x)=\sqrt{x}$
$(h\circ f)(-2)$
First, find $f(-2)$ by substituting $x$ by $-2$ in $f(x)$:
$f(-2)=(-2)^{2}-6(-2)+2=4+12+2=18$
Find $(h\circ f)(-2)$ by substituting $x$ by $18$ in $h(x)$:
$(h\circ f)(-2)=h(18)=\sqrt{18}=\sqrt{2\cdot9}=3\sqrt{2}\approx4.2426$
