Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.1 - The Algebra of Functions - Exercise Set - Page 842: 10


$(h\circ f)(-2)=3\sqrt{2}\approx42426$

Work Step by Step

$f(x)=x^{2}-6x+2;$ $h(x)=\sqrt{x}$ $(h\circ f)(-2)$ First, find $f(-2)$ by substituting $x$ by $-2$ in $f(x)$: $f(-2)=(-2)^{2}-6(-2)+2=4+12+2=18$ Find $(h\circ f)(-2)$ by substituting $x$ by $18$ in $h(x)$: $(h\circ f)(-2)=h(18)=\sqrt{18}=\sqrt{2\cdot9}=3\sqrt{2}\approx4.2426$
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