Answer
$(g\circ f)(-1)=-18$
Work Step by Step
$f(x)=x^{2}-6x+2;$ $g(x)=-2x$
$(g\circ f)(-1)$
First, find $f(-1)$ by substituting $x$ by $-1$ in $f(x)$:
$f(-1)=(-1)^{2}-6(-1)+2=1+6+2=9$
Find $(g\circ f)(-1)$ by substituting $x$ by $9$ in $g(x)$:
$(g\circ f)(-1)=g(9)=-2(9)=-18$
