#### Answer

$(h\circ g)(0)=0$

#### Work Step by Step

$g(x)=-2x;$ $h(x)=\sqrt{x}$
$(h\circ g)(0)$
First, find $g(0)$ by substituting $x$ by $0$ in $g(x)$:
$g(0)=-2(0)=0$
Find $(h\circ g)(0)$ by substituting $x$ by $0$ in $h(x)$:
$(h\circ g)(0)=h(0)=\sqrt{0}=0$