Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Review: 90


$x = -\dfrac{2000}{1999}$

Work Step by Step

$\log5x-\log(x+1)=4$ $\log \dfrac{5x}{x+1} = 4$ $10^{\log \frac{5x}{x+1}} = 10^4$ $\dfrac{5x}{x+1} = 10000$ $5x = 10000(x+1)$ $5x = 10000x+10000$ $9995x = -10000$ $x= -\dfrac{10000}{9995}$ $x = -\dfrac{2000}{1999}$
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