Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Review - Page 908: 106



Work Step by Step

Step 1: $\log_{2} (3x-1)=4$ Step 2: $3x-1=2^{4}$ Step 3: $3x-1=16$ Step 4: $3x=16+1$ Step 5: $3x=17$ Step 6: $x=\frac{17}{3}$ Therefore, the solution set is {$\frac{17}{3}$}.
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